58Ⅱ.左旋转字符串

参考链接

剑指offer_在线编程_牛客网

剑指 Offer 58 – II. 左旋转字符串-跟着帅地玩转校招，刷爆各类算法题帅地玩Offer

LCR 182. 动态口令 - 力扣（LeetCode）

个人尝试

class Solution {
    public String dynamicPassword(String password, int target) {
        StringBuilder sb = new StringBuilder();
        sb.append(password.substring(target, password.length()));
        sb.append(password.substring(0, target));
        return sb.toString();
    }
}

优秀题解

zhedahht/CodingInterviewChinese2: 《剑指Offer：名企面试官精讲典型编程面试题》第二版源代码

/*******************************************************************
Copyright(c) 2016, Harry He
All rights reserved.

Distributed under the BSD license.
(See accompanying file LICENSE.txt at
https://github.com/zhedahht/CodingInterviewChinese2/blob/master/LICENSE.txt)
*******************************************************************/

//==================================================================
// 《剑指Offer——名企面试官精讲典型编程题》代码
// 作者：何海涛
//==================================================================

char* LeftRotateString(char* pStr, int n)
{
    if(pStr != nullptr)
    {
        int nLength = static_cast<int>(strlen(pStr));
        if(nLength > 0 && n > 0 && n < nLength)
        {
            char* pFirstStart = pStr;
            char* pFirstEnd = pStr + n - 1;
            char* pSecondStart = pStr + n;
            char* pSecondEnd = pStr + nLength - 1;

            // 翻转字符串的前面n个字符
            Reverse(pFirstStart, pFirstEnd);
            // 翻转字符串的后面部分
            Reverse(pSecondStart, pSecondEnd);
            // 翻转整个字符串
            Reverse(pFirstStart, pSecondEnd);
        }
    }

    return pStr;
}